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Find the slope of a line perpendicular to the line passing through (– 3, 8) and (2, – 2). |
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Answer» Slope of the line passing through (– 3, 8) and (2, – 2), m1 = \(\frac{8 + 2}{− 3 − 2}\) = − 2. If m2 be the slope of the perpendicular line, then m1 m2 = – 1 ⇒ m2 = \(\frac{1}{2}\). |
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