1.

Find the smallest positive root of the equation `sqrt(sin(1-x))=sqrt(cos"x")`

Answer» `sqrt(sin(1-x)) = sqrtcosx`
`=>sin(1-x) = cosx`
`=>cos(pi/2-(1-x)) = cosx`
`=>pi/2-1+x = 2npi+-x`, where `n in Z.`
`=>x = (2npi-pi/2+1)/2`
As we have to find the smallest positive root of the equation,
it will come when `n = 2`.
`:. x = (4pi-pi/2 +1)/2`
`=>x = (7pi)/4+1/2.`


Discussion

No Comment Found

Related InterviewSolutions