1.

Find the total surface area ofa frustum whose slant height is 10 cm and having radii as 10 cm and 20 cm.(a) 1923.21 m^3(b) 2512 cm^2(c) 2184.21 m^3(d) 2842.21 m^3I had been asked this question at a job interview.This is a very interesting question from Surface Area & Volumes topic in portion Surface Area and Volumes of Mathematics – Class 10

Answer»

Correct OPTION is (B) 2512 CM^2

The best I can explain: s = 10 cm, R = 20 cm, r = 10 cm

Total surface area of a CONE = π(R + r)s + πR^2 + πr^2

= 3.14(20 + 10)10 + (3.14 × 20^2) + (3.14 × 10^2)

= 942 + 1256 + 314

= 2512 cm^2



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