1.

Find the value of `cot54^@/(tan36^@)+tan20^@/(cot70^@)`

Answer» Correct Answer - 2
`cot54^@/(tan36^@)+tan20^@/(cot70^@)=(cot(90^@-36^@))/(tan36^@)+(cot(90^@-70^@))/(cot70^@)`
`=tan36^@/(tan36^@)+cot70^@/(cot70^@)=2`


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