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Find the value of logxx + logxx3 + logxx5 + ........ + logxx(2n-1). |
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Answer» logxx + logxx3 + logxx5 + logxx5 + ........... + logxx2n-1 = logx x + 3 logx x + ..........+ (2n - 1 ) logx x = 1 + 3 + 5 + .......... + (2n - 1) = \(\frac{n}{2}\) [1+(2n - 1)] = n2 [ Using logx x = 1 and for A.P.Sn = \(\frac{n}{2}\) (a+l)] |
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