1.

Find the value of the expression `sec610^@cosec160^@-cot380^@tan470^@`

Answer» Correct Answer - -1
`sec610^@cosec160^@-cot380^@tan470^@`
`=sec(720^@-110^@)cosec(180^@-20^@)`
`-cot(360^@+20^@)tan(360^@+110^@)`
`=1/(cos110^@). 1/(sin20^@)-cot20^@tan110^@`
`= (-1)/sin^2 20^@+cot^2 20^@`
`=-[cosec^2 20^@-cot^2 20^@]`
`=-1`


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