Find the value of x which satisfies the relation Log10 3+log10 (4x+1)

1.	Find the value of x which satisfies the relation Log10 3+log10 (4x+1)=log10 (x+1)+1
Answer» log₁₀ 3+log₁₀ (4x+1)=log₁₀ (x+1)+1 Log₁₀ 3+log₁₀ (4x+1)=log₁₀ (x+1)+log₁₀ (x+1)+log₁₀ 10 Log₁₀ (3(4x+1))=log₁₀ (10(x+1)) =3(4x+1)=10(x+1)=12x+3 =10x+10 =2x=7 x=7/2

Find the value of x which satisfies the relation Log10 3+log10 (4x+1)=log10 (x+1)+1

Answer»

log₁₀ 3+log₁₀ (4x+1)=log₁₀ (x+1)+1

Log₁₀ 3+log₁₀ (4x+1)=log₁₀ (x+1)+log₁₀ (x+1)+log₁₀ 10

Log₁₀ (3(4x+1))=log₁₀ (10(x+1))

=3(4x+1)=10(x+1)=12x+3

=10x+10

=2x=7

x=7/2