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Find the values of `xa n dy`for which cosec `theta=(x^2-y^2)/(x^2+y^2)`is satisfied. |
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Answer» `x^2-y^2<=x^2+y^2` `cosectheta>=1` `cosectheta<=-1` `(x^2-y^2)/(x^2+y^2)=1` `x^2-y^2=a^2+y^2` `y=0` `(x^2-y^2)/(x^2+y^2)=-1` `x^2-y^2=-(x^2+y^2)` `x=0`. |
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