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Find the voltage across 2Ω resistor due to 20V source in the following figure.(a) -2.92(b) 2.92(c) 1.92(d) -1.92This question was posed to me during an internship interview.Question is taken from Superposition Theorem topic in portion Useful Theorems in Circuit Analysis of Network Theory

Answer»

The correct ANSWER is (a) -2.92

The best explanation: Short CIRCUITING 10V SOURCE, open circuiting 2A source,

The voltage at node A is (V-20)/7+V/20+V/10=0 => V = 9.76V. Now the voltage across 2Ω resistor is (V-20)/7×2=-2.92V.



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