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Find the volume of a regular hexagonal pyramid with height 18 m and base perimeter 24 m.1). 216 m32). 249.42 m33). 328.1 m34). 32.5 m3 |
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Answer» The BASE of a regular hexagonal pyramid has 6 EQUAL sides ∴ Side = base perimeter/6 = 24/6 = 4 m HEIGHT of pyramid = 18 m The $VOLUME of a $pyramid is = 1/3 × (the area of the base) × (the height)$ Area of the base = $ (3$( {\sqrt{3} })$/2) × (Side)2 Volume of regular hexagonal pyramid =(1/3)×(3$( {\sqrt{3} })$/2) × (Side)2 × height = ($( {\sqrt{3} })$/2) × (Side)2 × height ⇒ ($( {\sqrt{3} })$/2) × (4)2 ×18 = 249.42 m3 |
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