1.

Find thearea of cross-sectionof a rodthe diameterof whichismeasuredwith ascrewgaugewithreadings as shown in thefigure

Answer»

Solution :`(i) d_(1) =(1//2) ` of a metre =distanceof 2 kgfrom thesupport
(II) `d_(2) (1//4)` OFA metre
(iii) Find `W_(2)` USING thetheoremof momentsi.e., `w_(1)d_(1)= w_(2)d_(2)`
(iv) Mass =4 kg


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