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Find thearea of cross-sectionof a rodthe diameterof whichismeasuredwith ascrewgaugewithreadings as shown in thefigure |
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Answer» Solution :`(i) d_(1) =(1//2) ` of a metre =distanceof 2 kgfrom thesupport (II) `d_(2) (1//4)` OFA metre (iii) Find `W_(2)` USING thetheoremof momentsi.e., `w_(1)d_(1)= w_(2)d_(2)` (iv) Mass =4 kg |
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