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Find two rational numbers lying between \(\frac{-1}{3}\) and \(\frac{1}{2}.\) |
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Answer» Rational number between \(\frac{-1}{3}\) and \(\frac{1}{2}\) \(=\frac{1}{2}(\frac{-1}{3}+\frac{1}{2})\) \(=\frac{1}{2}(\frac{-1\times2+1\times3}{6})\) \(=\frac{1}{2}(\frac{-2+3}{6})\) = \(\frac{1}{2}\times\frac{1}{6}\) = \(\frac{1}{12}\) Now, \(=\frac{1}{2}(\frac{1}{12}+\frac{1}{2})\) \(=\frac{1}{2}(\frac{1+6}{12})\) \(=\frac{1}{2}\times\frac{7}{12}\) \(=\frac{7}{24}\) |
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