1.

Find which has greater resistance, 1 KW heater or a 100 W tungsten bulb, both marked for 230 V.

Answer»

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SOLUTION :`P_(1)=1KW=1000W,P2=100W,V=230V`
`P_(1)=(V_(2))/(R_(1))rArrR_(1)=(V_(2))/(P_(1))=(230xx230)/(1000)=52.9Omega`
`P_(2)=(V_(2))/(R_(2))rArrR_(2)=(V_(2))/(P_(2))=(230xx230)/(100)=529`
`therefore` 100 W BULB has more resisstance.


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