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Find x:x1-log2x = 0.01 |
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Answer» 21-log2x = 0.01 ⇒ 2 log22 - log2x = 0.01 = 1/100 ⇒ 2 log2(2/x) = 1/100 (\(\because\) log A - log B = log\(\frac{A}B\)) ⇒ \(\frac2x\) = \(\frac1{100}\) (\(\because\) alogax = x) ⇒ x = 2 x 100 = 200 |
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