1.

Find x:x1-log2x = 0.01

Answer»

21-log2x = 0.01

⇒ 2 log22 - log2x = 0.01 = 1/100

⇒ 2 log2(2/x) = 1/100 (\(\because\) log A - log B = log\(\frac{A}B\))

⇒ \(\frac2x\) = \(\frac1{100}\) (\(\because\) alogax = x)

⇒ x = 2 x 100 = 200



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