1.

Five resistors are connected in a circuit as shown. Find the ammeter reading when circuit is closed.

Answer»

SOLUTION :The resistance between the POINTS B and D is x
`x= (3Omegaxx6 Omega)/(3 Omega+6Omega) = 2 Omega`
Now the resistance of the whole combination is
` R= 0.5 Omega+x + 0.5 Omega`
`= 0.5 Omega +2.0 Omega + 0.5 Omega`
`:.` Ammeter READING `= (3V)/(3Omega)` = 1.0 AMPERE.


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