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For `0.1M` solution ,the colligative property will follow the orderA. `NaCl gt Na_(2)SO_(4)gt Na_(3)PO_(4)`B. `NaCl gt Na_(2)SO_(4)~~Na_(3)PO_(4)`C. `NaCl lt Na_(2)SO_(4) lt Na_(3)PO_(4)`D. `NaCl lt Na_(2)SO_(4)=Na_(3)PO_(4)` |
Answer» Correct Answer - C Colligative property in decreasing order `Na_(3)PO_(4)gtNa_(2)SO_(4)gtNaCl` `Na_(3)PO_(4)rarr3Na^(+)+PO_(4)^(3-)=4` `Na_(2)SO_(4)rarr2Na^(+)+SO_(4)^(2-)=3` `NaClrarrNa^(+)+Cl^(-)=2` |
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