For a body moving from position Xa to position Xb under a variable force, what is the work done?(a) W = F * (X2 – X1)(b) -W = F * (X2 – X1)(c) W = -F * (X2 – X1)(d) W = F * (X1 – X2)This question was posed to me during an interview.The origin of the question is Work-Energy Theorem for a Variable Force topic in division Work, Energy and Power of Physics – Class 11

For a body moving from position Xa to position Xb under a variable for

1.	For a body moving from position Xa to position Xb under a variable force, what is the work done?(a) W = F * (X2 – X1)(b) -W = F * (X2 – X1)(c) W = -F * (X2 – X1)(d) W = F * (X1 – X2)This question was posed to me during an interview.The origin of the question is Work-Energy Theorem for a Variable Force topic in division Work, Energy and Power of Physics – Class 11
Answer» The correct choice is (a) W = F * (X2 – X1) The explanation is: Kinetic energy (K) = 1/2 x m x v^2 dK/dt = mvdv/dt Force (F) = ma = mdv/dt dK/dt = Fv = mvdv/dt \(\int_{K1}^{K2}\) dK/dt = \(\int_{XA}^{Xb}\) F dX/dt \(\int_{K1}^{K2}\) dK = \(\int_{Xa}^{Xb}\) F * dX K2 – K1 = F (X2 – X1) W = F * (X2 – X1).

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