For a certain radioactive substance, it is observed that after `4h`, only `6.25%` of the original sample is left undeacyed. It follows that.A. the half life of the sample is `1` hourB. the mean life to the sample is `1//ln 2` hourC. the decay constant of the sample is `ln2 hour^(-1)`D. after a further `4` hours, the amount of the substance left over would be only `0.39%` of the original amount

For a certain radioactive substance, it is observed that after `4h`, o

1.	For a certain radioactive substance, it is observed that after `4h`, only `6.25%` of the original sample is left undeacyed. It follows that.A. the half life of the sample is `1` hourB. the mean life to the sample is `1//ln 2` hourC. the decay constant of the sample is `ln2 hour^(-1)`D. after a further `4` hours, the amount of the substance left over would be only `0.39%` of the original amount
Answer» Correct Answer - A::B::C::D 6.25% means, `N=(N_(0))/(16),` that means, `t=4T_(1//2)`

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