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For a d electron the orbital angular momentum isA. `sqrt(6)((h)/(2pi))`B. `sqrt(2)((h)/(2pi))`C. `((h)/(2pi))`D. `2((h)/(2pi))`

Answer» Correct Answer - A
The orbital angular momentum is `(h)/(2pi) sqrt(l(l + 1))`
The orbital angular momentum for an electron in d orbital `(l = 2)` is
`(h)/(2pi) sqrt(l(l + 1)) = (h)/(2pi) sqrt(2(2 + 1)) = (h)/(2pi) sqrt(6)`


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