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For a gas phase reaction Cl_(2) + CHCl_(3) to HCl+ "CC"l_(4), the rate law is given as r=k[Cl_(2)]^(1//2) [CHCl_(3)] . Explain how the rate of reaction varies when the concentration of chlorine is doubled . Give units of rate constant |
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Answer» Solution :(i) significant of rate law (ii) EQUATION for rate constant (iii) equation for rate constant with DOUBLE the CONCENTRATION of `Cl_(2)` (IV) COMPARISON of both the equations |
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