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For an electron, with n=3 has only one radial node. The orbital angular momentum of the electron will be :A. `0`B. `sqrt(6) h/(2pi)`C. `sqrt(2) h/(2pi)`D. `3(h/(2pi))` |
Answer» Correct Answer - C Number of radial nodes `=nl-1=1, n=3 :. l=1`. Orbital angular momentum `=sqrt(l(l+1)) (h)/(2pi)=sqrt(2) (h)/(2pi)` |
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