For an equilibrium reaction, `N_(2)O_(4)(g) hArr 2NO_(2)(g)`, the concentrations of `N_(2)O_(4)` and `NO_(2)` at equilibrium are `4.8 xx 10^(-2)` and `1.2 xx 10^(-2) mol//L` respectively. The value of `K_(c)` for the reaction isA. `3.3 xx 10^(2) mol L^(-1)`B. `3.3xx10^(-1) mol L^(-1)`C. `3.3 xx 10^(-3) mol L^(-1)`D. `3.3 xx 10^(3) mol L^(-1)`

For an equilibrium reaction, `N_(2)O_(4)(g) hArr 2NO_(2)(g)`, the conc

1.	For an equilibrium reaction, `N_(2)O_(4)(g) hArr 2NO_(2)(g)`, the concentrations of `N_(2)O_(4)` and `NO_(2)` at equilibrium are `4.8 xx 10^(-2)` and `1.2 xx 10^(-2) mol//L` respectively. The value of `K_(c)` for the reaction isA. `3.3 xx 10^(2) mol L^(-1)`B. `3.3xx10^(-1) mol L^(-1)`C. `3.3 xx 10^(-3) mol L^(-1)`D. `3.3 xx 10^(3) mol L^(-1)`
Answer» Correct Answer - C `N_(2)O_(4)(g) hArr 2NO_(2)(g)` `K_(c)=([NO_(2)]^(2))/([N_(2)O_(4)])=((1.2xx10^(-2)"mol"L^(-1))^(2))/(4.8xx10^(-2)"mol"L^(-1))` `=(1.44xx10^(-4)mol^(2)L^(-2))/(4.8xx10^(-2)"mol"L^(-1))` `=(14.4)/(4.8)xx10^(-3)"mol" L^(-1)` `=3.3xx10^(-3)"mol" L^(-1)`

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