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For`He^(Theta)` and `Li^(2+)` , the energies are relased to the quantum number n through an expression `E_(n) = (Z^(2)B)/(n^(2))` where Z is the atomic number species and `B = 2.179 xx 10^(-19) J` a.What is the energy of the lowest level of a `He^(Theta)` ion ? b. .What is the energy of the third level of a `Li^(2+)` ion ? |
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Answer» `E_(1)` for `He^(o+) = - (2^(2) xx2.179 xx 10^(-18))/(1^(2))` `= - 8.716 xx 10^(-18) J` b. `E_(3)` = for `LI^(2+) = - (3^(2)xx2.179 xx 10^(-18))/(3^(2))` `= - 2.179 xx 10^(-18) J` |
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