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For reaction, `PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g)` the value of `K_(c)` at `250^(@)C` is 26. The value of `K_(p)` at this temperature will be .A. 0.0006B. 0.57C. 0.83D. 0.46 |
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Answer» Correct Answer - A `K_(p)=K_(c) (RT)^(Deltan)=26(82.05xx523)^(-1)` `=(26)/(82.05xx523)=6.06xx10^(-4)` |
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