For the circuit given below, the cut-off frequency of the filter is ________________(a) 5283 kHz(b) 5283 Hz(c) 2653.1 kHz(d) 2653.1 HzI got this question during an interview.I'm obligated to ask this question of Advanced Problems on Filters in chapter Filters and Attenuators of Network Theory

For the circuit given below, the cut-off frequency of the filter is __

1.	For the circuit given below, the cut-off frequency of the filter is ________________(a) 5283 kHz(b) 5283 Hz(c) 2653.1 kHz(d) 2653.1 HzI got this question during an interview.I'm obligated to ask this question of Advanced Problems on Filters in chapter Filters and Attenuators of Network Theory
Answer» RIGHT answer is (d) 2653.1 Hz Easiest explanation: We know that, F = \(\frac{1}{2π×R×C}\) Where, R = 1200 Ω, C1 = 0.05×10^-6 F ∴ F = \(\frac{1}{2π×1200×C}\) = \(\frac{1}{2π×60×10^{-6}}\) = \(\frac{10^6}{2π×60}\) = 2653.1 Hz.

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For the circuit given below, the cut-off frequency of the filter is ________________(a) 5283 kHz(b) 5283 Hz(c) 2653.1 kHz(d) 2653.1 HzI got this question during an interview.I'm obligated to ask this question of Advanced Problems on Filters in chapter Filters and Attenuators of Network Theory

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