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For the circuit given in figure below, the Thevenin equivalent as viewed from terminals y and y’ is _________(a) 8 V and 32 Ω(b) 4 V and 32 Ω(c) 5 V and 6 Ω(d) 7 V and 6 ΩThe question was asked in an online interview.My doubt stems from Thevenin Theorem Involving Dependent and Independent Sources in division Useful Theorems in Circuit Analysis of Network Theory

Answer» CORRECT choice is (d) 7 V and 6 Ω

The explanation: We, Thevenized the left side of xx’ and source transformed RIGHT side of yy’.

Thevenin EQUIVALENT as seen from TERMINAL yy’ is

Vxx’ = Vth = \(\displaystyle\frac{\frac{4}{24} + \frac{8}{8}}{\frac{1}{24} + \frac{1}{8}}\) = 5V

= \(\frac{0.167+1}{0.04167+0.125}\) = 7 V

RTH = (8 + 16) || 8

= \(\frac{24×8}{24+8}\) = 6 Ω.


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