InterviewSolution
Saved Bookmarks
| 1. |
For the circuit given in figure below, the Thevenin equivalent as viewed from terminals y and y’ is _________(a) 8 V and 32 Ω(b) 4 V and 32 Ω(c) 5 V and 6 Ω(d) 7 V and 6 ΩThe question was asked in an online interview.My doubt stems from Thevenin Theorem Involving Dependent and Independent Sources in division Useful Theorems in Circuit Analysis of Network Theory |
|
Answer» CORRECT choice is (d) 7 V and 6 Ω The explanation: We, Thevenized the left side of xx’ and source transformed RIGHT side of yy’. Thevenin EQUIVALENT as seen from TERMINAL yy’ is Vxx’ = Vth = \(\displaystyle\frac{\frac{4}{24} + \frac{8}{8}}{\frac{1}{24} + \frac{1}{8}}\) = 5V = \(\frac{0.167+1}{0.04167+0.125}\) = 7 V ∴ RTH = (8 + 16) || 8 = \(\frac{24×8}{24+8}\) = 6 Ω. |
|