For the following equilibrium `:` `NH_(2)CO_(2)NH_(4)(s)hArr 2NH_(3)(g)+CO_(2)(s)` `K_(p)` is found to be 0.5 at 4400 K . Hence, partial pressure of `NH_(3)` and `CO_(2)` are respectively `:`A. 2.0,1.0 atmB. 1.0,2.0 atmC. 1.0,0.5 atmD. 0.5,1.0 atm

For the following equilibrium `:` `NH_(2)CO_(2)NH_(4)(s)hArr 2NH_(3)(g

1.	For the following equilibrium `:` `NH_(2)CO_(2)NH_(4)(s)hArr 2NH_(3)(g)+CO_(2)(s)` `K_(p)` is found to be 0.5 at 4400 K . Hence, partial pressure of `NH_(3)` and `CO_(2)` are respectively `:`A. 2.0,1.0 atmB. 1.0,2.0 atmC. 1.0,0.5 atmD. 0.5,1.0 atm
Answer» Correct Answer - C `NH_(2)CONH_(4)(s)hArr 2NH_(3)(g)+CO_(2)(g)` `K_(p)=(p_(NH_(3)))^(2)(p_(CO_(2)))` Let `p_(CO_(2))=x:. p_(NH_(3))=2x` `:. (2x)^(2).x=0.5` `4x^(3)=0.5` `x^(3)=(5)/(40)=(1)/(8)` `x=(1)/(2)=0.5` `:. P_(CO_(2))=0.5,p_(NH_(3))=2xx0.5=1.0` `p_(NH_(3))=1.0` and `p_(CO_(2))=0.5`

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For the following equilibrium `:` `NH_(2)CO_(2)NH_(4)(s)hArr 2NH_(3)(g)+CO_(2)(s)` `K_(p)` is found to be 0.5 at 4400 K . Hence, partial pressure of `NH_(3)` and `CO_(2)` are respectively `:`A. 2.0,1.0 atmB. 1.0,2.0 atmC. 1.0,0.5 atmD. 0.5,1.0 atm

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