For the reaction X → Y + Z, the rate constant is 0.00058 s^-1. What percentage of X will be decomposed in 50 minutes?(a) 90.02 percent(b) 82.44 percent(c) 88.82 percent(d) 82.67 percentThe question was asked in a national level competition.My question is taken from Chemical Kinetics in portion Chemical Kinetics of Chemistry – Class 12

For the reaction X → Y + Z, the rate constant is 0.00058 s^-1. What

1.	For the reaction X → Y + Z, the rate constant is 0.00058 s^-1. What percentage of X will be decomposed in 50 minutes?(a) 90.02 percent(b) 82.44 percent(c) 88.82 percent(d) 82.67 percentThe question was asked in a national level competition.My question is taken from Chemical Kinetics in portion Chemical Kinetics of Chemistry – Class 12
Answer» The correct CHOICE is (b) 82.44 percent To elaborate: Given, rate CONSTANT k= 0.00058 s^-1 Time t= 50 minutes = 50 × 60 = 3000 seconds First-order integrated rate equation, k = \(\FRAC{2.303}{t}\)log\(\frac{100}{100-a}\) log\(\frac{100}{100-a}\) = \(\frac{kt}{2.303}\) log\(\frac{100}{100-a}\) = \(\frac{0.00058 \times 3000}{2.303}\) = 0.756 a=82.44 percent.

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