1.

What is the time required for 75 percent completion of a first-order reaction?(a) 3 × t50(b) 4 × t50(c) 4.5 × t50(d) 2 × t50This question was addressed to me in homework.This question is from Chemical Kinetics in division Chemical Kinetics of Chemistry – Class 12

Answer»

Right choice is (d) 2 × t50

For EXPLANATION I WOULD SAY: Given, the reaction is 75 percent complete so, a = 75

We know, t = \(\frac{2.303}{k}\)log\(\frac{100}{100-a}\)

T75 = \(\frac{2.303}{k}\)log\(\frac{100}{100-75}\) = \(\frac{1.386}{k}\)

t50 = \(\frac{2.303}{k}\)log\(\frac{100}{100-50}\) = \(\frac{0.693}{k}\)

t75 = 2 × t50.



Discussion

No Comment Found

Related InterviewSolutions