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What is the rate law of hydrolysis of CH3COOC2H5 in aqueous solution?(a) R=k [CH3COOC2H5]^2(b) R=k [CH3COOC2H5](c) R=k [CH3COOC2H5] [H2O](d) R=kk’ [CH3COOC2H5][H2O]This question was posed to me in an interview.This interesting question is from Chemical Kinetics in section Chemical Kinetics of Chemistry – Class 12

Answer»

Correct option is (B) R=k [CH3COOC2H5]

The explanation: The reaction involved in acid hydrolysis of ester = CH3COOC2H5 + H2O → CH3COOH + C2H5OH. So the rate law becomes R=k’ [CH3COOC2H5][H2O], SINCE water is present in LARGE excess it is assumed to be constant throughout the reaction.

R=k[CH3COOC2H5], where k is k’ [H2O].



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