For the series circuit given below, the value of the cut-off frequencies are ____________(a) 78.235 kHz; 16.215 kHz(b) 13.135 kHz; 81.531 kHz(c) 16.716 kHz; 15.124 kHz(d) 50.561 kHz; 18.686 kHzThe question was asked by my college director while I was bunking the class.This is a very interesting question from Problems of Series Resonance Involving Quality Factor in chapter Resonance & Magnetically Coupled Circuit of Network Theory

For the series circuit given below, the value of the cut-off frequenci

1.	For the series circuit given below, the value of the cut-off frequencies are ____________(a) 78.235 kHz; 16.215 kHz(b) 13.135 kHz; 81.531 kHz(c) 16.716 kHz; 15.124 kHz(d) 50.561 kHz; 18.686 kHzThe question was asked by my college director while I was bunking the class.This is a very interesting question from Problems of Series Resonance Involving Quality Factor in chapter Resonance & Magnetically Coupled Circuit of Network Theory
Answer» Right option is (c) 16.716 kHz; 15.124 kHz Best explanation: Resonant Frequency, FR = \(\frac{1}{2π\sqrt{LC}} \) = \(\frac{1}{6.28\sqrt{(5 × 10^{-3})(0.02 × 10^{-6})}}\) = \(\frac{1}{6.28\sqrt{10^{-10}}}\) = \(\frac{1}{6.28 × 10^{-5}}\) = 15.9 kHz. Inductive REACTANCE, XL = 2πfL = (6.28) (15.92 × 10^3)(5 × 10^-6) = 0.5 kΩ ∴ QUALITY factor Q = \(\frac{X_L}{R} = \frac{0.5 kΩ}{50}\) = 10 ∴ ∆F = \(\frac{f}{Q} = \frac{15.9 kHz}{10}\) = 1.592 kHz ∴ BANDWIDTH = \(\frac{∆F}{2}\) = ±796 Hz. Therefore, f2 = f + \(\frac{∆F}{2}\) = 16.716 kHz and f1 = f – \(\frac{∆F}{2}\) = 15.124 kHz.

Discussion

No Comment Found

Related InterviewSolutions

The meter constant of a single-phase, 230 V induction watt-meter is 600 rev/kW-h. The speed of the meter disc for a current of 15 A at 0.8 power factor lagging will be?(a) 30.3 rpm(b) 25.02 rpm(c) 27.6 rpm(d) 33.1 rpmI got this question in an international level competition.Asked question is from Advanced Problems on Magnetically Coupled Circuits in chapter Resonance & Magnetically Coupled Circuit of Network Theory
Consider a circuit consisting of two capacitors C1 and C2. Let R be the resistance and L be the inductance which are connected in series. Let Q1 and Q2 be the quality factor for the two capacitors. While measuring the Q value by the Series Connection method, the value of the Q factor is?(a) Q = \(\frac{(C_1 – C_2) Q_1 Q_2}{Q_1 C_1-Q_2 C_2}\)(b) Q = \(\frac{(C_2 – C_1) Q_1 Q_2}{Q_1 C_1-Q_2 C_2}\)(c) Q = \(\frac{(C_1 – C_2) Q_1 Q_2}{Q_2 C_2-Q_1 C_1}\)(d) Q = \(\frac{(C_2 – C_1) C_1 C_2}{Q_1 C_1-Q_2 C_2}\)This question was posed to me by my college professor while I was bunking the class.This intriguing question originated from Advanced Problems on Magnetically Coupled Circuits topic in section Resonance & Magnetically Coupled Circuit of Network Theory
A moving iron ammeter produces a full-scale torque of 240 μN-m with a deflection of 120° at a current of 10 A. the rate of change of self-inductance (μH/rad) of the instrument at full scale is?(a) 2.0 μH/rad(b) 4.8 μH/rad(c) 12.0 μH/rad(d) 114.6 μH/radThis question was addressed to me in an international level competition.I would like to ask this question from Advanced Problems on Magnetically Coupled Circuits in chapter Resonance & Magnetically Coupled Circuit of Network Theory
The relation between the Q factor of a coil measured by the Q Meter and the actual Q of the coil is _________(a) Equal to(b) Same but somewhat lesser than(c) Same but somewhat higher than(d) Not equal toThe question was asked in an interview for internship.My question comes from Advanced Problems on Magnetically Coupled Circuits in portion Resonance & Magnetically Coupled Circuit of Network Theory
The average power absorbed by an impedance Z = 30 – j 70 Ω when a voltage V = 120∠0° is applied is _____________(a) 35(b) 37.24(c) 45(d) 50.25This question was addressed to me during an online interview.Origin of the question is Advanced Problems on Magnetically Coupled Circuits topic in chapter Resonance & Magnetically Coupled Circuit of Network Theory
A current of [2 + \(\sqrt{2}\)sin (314t + 30) + 2\(\sqrt{2}\)cos (952t +45)] is measured with a thermocouple type, 5A full scale, class 1 meter. The meter reading would lie in the range?(a) 5 A ± 1 %(b) (2 + 3\(\sqrt{2}\)) A ± 1%(c) 3 A ± 1.7 %(d) 2 A ± 2.5 %I have been asked this question in an interview for job.The doubt is from Advanced Problems on Magnetically Coupled Circuits in section Resonance & Magnetically Coupled Circuit of Network Theory
The CT supplies current to the current coil of a wattmeter power factor meter, energy meter and, an ammeter. These are connected as?(a) All coils in parallel(b) All coils in series(c) Series-parallel connection with two in each arm(d) Series-parallel connection with one in each armThis question was posed to me in an interview for job.My query is from Advanced Problems on Magnetically Coupled Circuits topic in portion Resonance & Magnetically Coupled Circuit of Network Theory
A 50 Hz voltage is measured with a moving iron voltmeter and a rectifier type AC voltmeter connected in parallel. If the meter readings are VA and VB respectively. Then the form factor may be estimated as?(a) \(\frac{V_A}{V_B}\)(b) \(\frac{1.11V_A}{V_B}\)(c) \(\frac{\sqrt{2} V_A}{V_B}\)(d) \(\frac{πV_A}{V_B}\)The question was asked by my school teacher while I was bunking the class.My query is from Advanced Problems on Magnetically Coupled Circuits in portion Resonance & Magnetically Coupled Circuit of Network Theory
A (350 A/7A), 50 Hz current transformer has a primary bar. The secondary has a pure resistance of 1 Ω. It also draws a current of 5 A. The magnetic core requires 350 AT for magnetization. Find the percentage ratio error.(a) 10.56(b) -28.57(c) 11.80(d) -11.80This question was posed to me by my school teacher while I was bunking the class.Asked question is from Advanced Problems on Magnetically Coupled Circuits topic in chapter Resonance & Magnetically Coupled Circuit of Network Theory
The inductance of a certain moving- iron ammeter is expressed as L = 10 + 3θ – \(\frac{θ^2}{4}\) μH, where θ is the deflection in radian from the zero position. The control spring torque is 25 × 10^-6 Nm/rad. If the meter is carrying a current of 5 A, the deflection is ____________(a) 2.4(b) 2.0(c) 1.2(d) 1.0This question was posed to me by my college director while I was bunking the class.This intriguing question comes from Advanced Problems on Magnetically Coupled Circuits topic in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment