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For the series resonant circuit given below, the value of the total current flowing through the circuit is ____________(a) 7.521 mA(b) 6.327 mA(c) 2.168 mA(d) 9.136 mAThis question was addressed to me during an interview for a job.This question is from Problems of Parallel Resonance Involving Quality Factor in division Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

Right OPTION is (a) 7.521 mA

Easy explanation: Resonant Frequency, \(\frac{1}{2π\sqrt{LC}} \)

= \(\frac{1}{6.28\sqrt{(4.7×10^{-3})(0.001×10^{-6})}}\)

= \(\frac{1}{6.28\sqrt{4.7×10^{-12}}}\)

= \(\frac{1}{1.362×10^{-5}}\) = 73.412 kHz

Inductive Reactance, XL = 2πfL = (6.28) (73.142 × 10^3)(4.7 × 10^-6)

= 2.168 kΩ

Capacitive Reactance, XC = \(\frac{1}{2πfC} = \frac{1}{(6.28)(73.142×10^3)(0.001×10^{-6})}\)

= \(\frac{1}{4.613×10^{-4}}\) = 2.168 kΩ

ZEQ = R = 47 Ω

IT = \(\frac{V_{in}}{Z_{EQ}}= \frac{V_{in}}{R} = \frac{0.3535}{47}\) = 7.521 mA.



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