1.

Forces of magnitudes 5 and 3 units acting in the directions ` 6hati + 2hatj + 3hatk and 3 hati - hati +6hatk` respectively act on a particle which is displaced from the point ( 2,2,-1) to ( 4,3,1) . The work done by the forces, isA. 148 unitB. ` 148/7` unitC. 296 unitsD. none of these

Answer» Correct Answer - B
Let ` vecF` be the resultant force and `vecd` be the displacement vector. Then,
` vecF=5 ((6hati +2hatj +3hatk))/ (sqrt(36+4+9))+3 ((3hati -2hatj +6hatk)) /(sqrt(9 +4+ 36)) = 1/7 (39 hati + 4hatj +33 hatk)`
` and vecd = (4hati + 3hatj +hatk) - (2hati +2hatj -hatk) = 2hati +hatj + 2hatk`
Total work done = ` vecF. vecd`
`Rightarrow ` Total work done = ` 1/7 (39 hati +4hatj +33hatk).(2hati +hatj +2hatk) `
Total work done ` = 1/7 ( 78 +4 +66) = 148/7` units.


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