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Four friends had a competition to see how far could they hop on one foot. The table given shows the distance covered by each.NameDistance covered (Km)Seema1/25Nancy1/32Megha1/40Soni1/20(a) How farther did Soni hop than Nancy?(b) What is the total distance covered by Seema and Megha?(c) Who walked farther, Nancy or Megha? |
Answer» The LCM of the denominators 25, 32, 40 and 20 is 800 ∴ 1/25 = [(1×32)/ (25×32)] = (32/800) (1/32) = [(1×25)/ (32×25)] = (25/800) (1/40) = [(1×20)/ (40×20)] = (20/800) (1/20) = [(1×40)/ (20×40)] = (40/800) Then, (a) Soni hop more than Nancy = (40/800) – (25/800) = (40 – 25)/800 = (15/800) = 3/160 km (b) The total distance covered by Seema and Megha = (32/800) + (20/800) = (32 + 20)/800 = (52/800) = 13/200 km (c) Nancy walked farther. |
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