1.

Four point masses each of the value m, are placed at the corner of a square ABCD of side l. The moment of inertia of this system about an axis passing through A parallel to B D is

Answer»

`3 ml^(2)`
`ml^(2)`
`2ML^(2)`
`sqrt(3)ml^(2)`

Solution :`AC = BD = sqrt(2)l`
`I_(BD) = m(AO)^(2) + m(CO)^(2) = ml^(2)`


Discussion

No Comment Found

Related InterviewSolutions