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\((\frac{2}{3}+\frac{-4}{5}+\frac{7}{15}+\frac{-11}{20})=\,?\)A. \(\frac{-1}{5}\)B. \(\frac{-4}{15}\)C. \(\frac{-13}{60}\)D. \(\frac{-7}{30}\) |
Answer» \(\frac{2}{3}+\frac{-4}{5}+\frac{7}{15}+\frac{-11}{20}\) LCM of 3, 5, 15, 20 \(=\frac{2\times20+(-4)\times12+7\times4+(-11)\times3}{60}\) \(=\frac{40-48+28-33}{60}\) \(=\frac{68-81}{60}\) \(=\frac{-31}{60}\) |
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