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\((\frac{-3}{7})^{-1}= \,?\)A. \(\frac{7}{3}\)B. \(\frac{-7}{3}\)C. \(\frac{3}{7}\)D. none of these |
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Answer» We know,For any real number a≠0, \(a^{-1}=\frac{1}{a}\,\,so,(\frac{-3}{7})^{-1}\) \(=\frac{7}{-3}=\frac{7\times-1}{-3\times-1}=\frac{-7}{3}\) |
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