1.

\((\frac{7}{-26}+\frac{16}{39})=\,?\)A. \(\frac{11}{78}\)B. \(\frac{-11}{78}\)C. \(\frac{11}{39}\)D. \(\frac{-11}{39}\)

Answer»

\(\frac{7}{-26}=\frac{7\times-1}{-26\times-1}=\frac{-7}{26}\)

\(\Rightarrow\) \(\frac{7}{-26}+\frac{16}{39}=\frac{-7}{26}+\frac{16}{39}\)

\(=\frac{-7\times3+16\times2}{78}\)

\(=\frac{-21+32}{78}\)

\(=\frac{11}{78}\)



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