

InterviewSolution
Saved Bookmarks
1. |
\((\frac{7}{-26}+\frac{16}{39})=\,?\)A. \(\frac{11}{78}\)B. \(\frac{-11}{78}\)C. \(\frac{11}{39}\)D. \(\frac{-11}{39}\) |
Answer» \(\frac{7}{-26}=\frac{7\times-1}{-26\times-1}=\frac{-7}{26}\) \(\Rightarrow\) \(\frac{7}{-26}+\frac{16}{39}=\frac{-7}{26}+\frac{16}{39}\) \(=\frac{-7\times3+16\times2}{78}\) \(=\frac{-21+32}{78}\) \(=\frac{11}{78}\) |
|