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\(\frac{a}{y-z}=\frac{b}{z-x}=\frac{c}{x-y }\) = then ax + by + cz = ………………a/y-z = b/z-x = c/x-y A) -a B) – b C) 0 D) -1 |
Answer» Correct option is (C) 0 \(\frac{a}{y-z}=\frac{b}{z-x}=\frac{c}{x-y}\) \(=\frac{ax+by+cz}{x(y-z)+y(z-x)+z(x-y)}\) \(=\frac{ax+by+cz}{xy-xz+yz-xy+xz-yz}\) \(=\frac{ax+by+cz}0\) \(\Rightarrow\) ax+by+cz = 0. Correct option is C) 0 |
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