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From a measurement of the freezing point depression of benzene, the molecular weight of acetic acid in a benzene solution was determined to be `100`. The percentage association of acetic acid isA. `100%`B. `79%`C. `93%`D. `83%` |
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Answer» Correct Answer - 2 We can find degree of association as follows: `alpha=(M_(t)-M_(o))/M_(o)(n/(1-n))` where `M_(o)` is the observed molar mass and `M_(t)` is the theoretical molar mass. Here, we have `M_(o)=100 g//"mole"` `M_(t)=(12xx2+1xx4+16xx2)=60 g mol^(-1)` `n=2` Substituting these values, we get `alpha=(60-100)/100(2/(1-2))` `=80/100=0.8` percentage association `=0.8xx100%` `=80%` |
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