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From a rifle of mass 4 kg, a bullet of mass 50g is fired with an initial velocity of 35ms^(-1). Calculate the initial recoil velocity of the rifle. |
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Answer» Solution :MASS of the rifle, `M_1 =4KG` Mass of the bullet, `M_2 =50g=0.05 KG` Recoilvelocity of the rifle `=V_1` Bullet is fired with ainitial velocity `V_2= 35 m//s` Initially, the rifleis at rest , Thus its initial velocity , v=0 Total initial momentum of the rifle and bullet system `=(m_1+m_2)` V=0 Total momentum of the rifle and bullet system after firing `=m_1v_1 +m_2v_2=0.05x25=4v_1+1.75`. According to the law of conservation of momentum, Total momentum afterthe firing `=0,V_1=1.75//4=0.4375m//s`. The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s. |
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