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From a rope 11 m long. two pieces of lengths \(2\frac{3}{5}\) m and \(3\frac{3}{10}\) m are cut off. What is the length of remaining rope? |
Answer» Length of rope = 11 m Length of first piece cut = \(2\frac{3}{5}\) m Length of second piece cut = \(3\frac{3}{10}\) m Total length cut = Length of first piece cut + Length of second piece cut = \(2\frac{3}{5}\)m + \(3\frac{3}{10}\)m = \(\frac{13}{5}\)m + \(\frac{33}{10}\)m = \(\frac{26+33}{10}\)m = \(\frac{59}{10}\)m Length of remaining rope = Length of rope - Total length cut = 11m - \(\frac{59}{10}\)m = \(\frac{110-59}{10}\)m = \(\frac{51}{10}\)m = \(5\frac{1}{10}\)m Hence, Length of remaining rope \(5\frac{1}{10}\)m |
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