1.

From the top of a tower 100 m in height a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 25 m/s. Find when and where the two balls will meet ? (g = 9.8 m/s)

Answer»

SOLUTION :For the ball CHAPPED from the top
`x=4.9t^(2)"" ...(i)`
For the ball thrown UPWARDS
`100-x=25t-4.9t^(2)"" ...(ii)`
From eq. (i) & (ii),
`t=4s, x=78.4m`


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