1.

Given, (23x + 1 × 42y + 1 = 2z – x). If (x + y) = 1, find the value of z.1). 32). 53). 74). 9

Answer»

GIVEN,

⇒ 23x + 1 × 42y + 1 = 2z – X

⇒ 23x + 1 × 22(2y + 1) = 2z – x

⇒ 2(3x + 1 + 4y + 2) = 2z – x

Equating the powers of 2,

⇒ 3x + 4y + 3 = z – x

⇒ z = 4x + 4y + 3

⇒ z = 4(x + y) + 3

Putting (x + y) = 1,

∴ z = 4 + 3 = 7


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