1.

Given : force = (alpha)/("density" + beta^3). What are the dimensions of alpha, beta ?

Answer»

`ML^(–2) T^(–2) ,ML^(–1//3)`
`M^(2) L^(4) T^(–2),M^(1//3) L^(–1)`
`M^(2) L^(–2) T^(–2), M^(1//3) L^(–1)`
`M^(2) L^(–2) T^(–2), M L^(–3)`

Solution :DIMENSION of`β^(3)` = dimension of density
Solve, `beta=[M^(1//3)L^(-1)]`
Force = `(alpha)/("density")`
`alpha` = Force `xx` density
`=[MLT^(-2)ML^(-3)]`
`=[M^(2)L^(-2)T^(-2)]`


Discussion

No Comment Found

Related InterviewSolutions