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Given that, R1 = 36 Ω and R2 = 75 Ω, each having tolerance of ±5% are connected in series. The value of resultant resistance is ___________(a) 111 ± 0 Ω(b) 111 ± 2.77 Ω(c) 111 ± 5.55 Ω(d) 111 ± 7.23 ΩI had been asked this question in examination.The doubt is from Advanced Problems on Network Theorems topic in section Useful Theorems in Circuit Analysis of Network Theory

Answer» RIGHT choice is (c) 111 ± 5.55 Ω

Best explanation: R1 = 36 ± 5% = 36 ± 1.8 Ω

R2 = 75 ± 5% = 75 ± 3.75 Ω

∴ R1 + R2 = 111 ± 5.55 Ω.


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