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Given two voltages, V1 = sin (ωt + 60°) and V2 = cos (ωt). Which of the following is correct?(a) V1 is leading V2 by 15°(b) V1 is leading V2 by 30°(c) V2 is leading V1 by 60°(d) V2 is leading V1 by 30°This question was addressed to me during an interview for a job.My question is from Advanced Problems on Network Theorems topic in portion Useful Theorems in Circuit Analysis of Network Theory

Answer»

The correct answer is (C) V2 is leading V1 by 60°

For explanation I WOULD say: Given that, V1 = SIN (ωt + 30°) and V2 = cos (ωt)

Now, V2 can be WRITTEN as,

V2 = sin (ωt + 90°).

Hence, V2 is leading V1 by (90 – 30) = 60°.



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