1.

Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:A. `1`B. `1.5`C. `0.25`D. `2.5`

Answer» Correct Answer - A
logx/M=log K+1/n log P`
`1/n=tan 45^(@)" "ln k=0.69`
`n=1" "k=2`
`x/m=2xx(0.5)^(1)`
`x=1`


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