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Graph between `log x//m` and `log p` is a straight line inclined at an angle of `45^@` . When pressure is `0.5 atm` and `1n k = 0.693`, the amount of solute adsorbed per gram of adsorbent will be:A. `1`B. `1.5`C. `0.25`D. `2.5` |
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Answer» Correct Answer - A logx/M=log K+1/n log P` `1/n=tan 45^(@)" "ln k=0.69` `n=1" "k=2` `x/m=2xx(0.5)^(1)` `x=1` |
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