1.

Half life of a radioactive sample is `2x` years. What fraction of this sample will remain undecayed after `x` years?

Answer» `K = (2.303)/(t) log ((N_(0))/(N))`
`(0.693)/(t_(1//2)) = (2.303)/(t) log ((N_(0))/(N))`
`(0.693)/(2x) = (2.303)/(x) log ((N_(0))/(N))`
`(1)/(2) log 2 = log ((N_(0))/(N))`
`(N)/(N_(0)) = (1)/(sqrt(2))`
Fraction undecayed `= (1)/(sqrt(2))`


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