1.

Hardness of a water sample is ` 100 "ppm" CaCo_(3) `. Thus molarity of ` CaCO_(3) `isA. ` 2xx10^(-3)M `B. ` 1xx10^(-3) M `C. ` 2xx10^(-2)M `D. ` 2xx10^(-4) M`

Answer» Correct Answer - B
Hard water has hardness `= 100 "ppm"`
Thus , `10^(6) ml (=10^(3))` water has `CaCO_(3) = 100 g = 1 mol`
Thus, molarity `= ("Moles")/("Litre") = (1)/(10^(3))= 1xx10^(-3) M`


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